Q3. The following particulars apply to a ship of length 140 m when floating in sea water of density 1025 kg/m3 at an even keel draught of 7.265 m.
displacement = 15800 tonne
centre of gravity above the keel (KG) = 7.8 m
centre of buoyancy above the keel (KB) = 4.05 m
waterplane area = 2146 m2
centre of flotation from midships (LCF) = 3.0 m aft
second moment of area of the waterplane about a transverse axis through midships = 2.305 × 106 m4
(a) Calculate the value of the moment to change trim by one centimetre (MCT 1 cm) in the above condition. (6)
(b) The ship in the above condition now undergoes the following changes in loading:
352 tonne added at an Lcg of 10.5 m forward of midships
110 tonne removed from an Lcg of 2.0 m aft of midships
150 tonne restowed at a new position 52.7 m aft of its original position.
Calculate the new end draughts of the ship. (10)
Please buy a membership plan and login via our app to view answers.