Q3. The following particulars apply to a ship of length 140 m when floating in sea water of density 1025 kg/m3 at an even keel draught of 7.265 m.
displacement = 15800 tonne
centre of gravity above the keel (KG) = 7.8 m
centre of buoyancy above the keel (KB) = 4.05 m
waterplane area = 2146 m2
centre of flotation from midships (LCF) = 3.0 m aft
second moment of area of the waterplane about a transverse axis through midships = 2.305 × 106 m4
(a) Calculate the value of the moment to change trim by one centimetre (MCT1cm) in the above condition. (6)
(b) The ship in the above condition now undergoes the following changes in loading:
352 tonne added at an Lcg of 10.5 m forward of midships
110 tonne removed from an Lcg of 2.0 m aft of midships
150 tonne restowed at a new position 52.7 m aft of its original position.
Calculate the new end draughts of the ship. (10)
Please buy a membership plan and login via our app to view answers.