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Q3. The sag d metres, in a cable of length, L metres, when suspended between two points and subject to a tension, T Newtons, may be determined from the formula:

d² - T/w d + 1/4 L² = 0

Where w is the weight in Newtons per metres run.

Calculate, correct to two decimal places, the sag in the cable when T = 2 200 N, L = 40 m and the total weight of the cable = 220 N, (a) (8)

(b) Solve for x in the following equation:

3/(x² - 9) + 2/(x - 3) = 3/(x² - 2x - 3) (8)