Q6. A spade type rudder, supported only at the rudder head, has a depth of 4.8 m, with the following widths at equal intervals commencing from the top of the rudder.
2.80, 2.75, 2.40, 1.95 and 1.50 m
The top of the rudder is 0.4 m from the bearing at the rudder head.
The centre of effort of the rudder can be taken to act at the vertical centroid of the rudder and at a distance of 0.2 m from the axis of rotation.
The force on the rudder, normal to the plane of the rudder is given by the expression:
Fn = 18 A V2 α newtons
where: A = rudder area (m2)
V = ship speed (m/s)
α = rudder angle (degrees)
The equivalent twisting moment (TE) is given by:
TE = M + √(M2 + T2 )
where: M = bending moment
T = twisting moment
Calculate the required diameter of the rudder stock, assuming a maximum allowable stress of 75 MN/m2, for a ship speed of 20 knots and rudder angle 35°.
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