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Academics – Naval Architecture : 2018/OCT/03
Question

Q3. A ship of length 240 m has draught marks 6.0 m aft of the forward perpendicular and 10.0 m forward of the after perpendicular.

The draughts at the marks are 8.8 m aft and 7.6 m forward.

For this condition, the following hydrostatic data are available:

LCF = 2.4 m aft of midships

Displacement = 65000 tonne

GML =120 m

LCB = 1.4 m aft of midships

Calculate EACH Of the following:

(a) the true mean draught; (4)

(b) the draughts at the perpendiculars; (4)

(c) the longitudinal position of the centre of gravity.  (8)

Asked in Year/Month/Ques No.
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