Academics – Naval Architecture : 2018/OCT/03
Question
Q3. A ship of length 240 m has draught marks 6.0 m aft of the forward perpendicular and 10.0 m forward of the after perpendicular.
The draughts at the marks are 8.8 m aft and 7.6 m forward.
For this condition, the following hydrostatic data are available:
LCF = 2.4 m aft of midships
Displacement = 65000 tonne
GML =120 m
LCB = 1.4 m aft of midships
Calculate EACH Of the following:
(a) the true mean draught; (4)
(b) the draughts at the perpendiculars; (4)
(c) the longitudinal position of the centre of gravity. (8)
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